Select the type of thickener and specifications, necessary to meet the lower water content of the job to concentrate or ore requirements, but strict control and reduce the loss of metal with the overflow amount and the overflow of water turbidity. Therefore, when designing the concentrator design, the effective area of ​​the concentrator should be determined by production test or simulation test; if the system test is carried out unconditionally, it must be calculated according to the relevant parameters of the slurry static settlement test and the settlement test curve. select; only accurately grasp the characteristics of the concentrated slurry under conditions similar reference process before production plant ores selected indicators.
Commonly used concentrators are available in both central and peripheral transmissions. The specifications of the concentrator are mainly determined according to the rate of sedimentation of the largest particles or aggregates in the overflow and the aggregate in the overflow. Therefore, when selecting a thickener, factors that affect the settling velocity must be considered, such as the liquid-solid ratio of the ore and discharge, the particle size composition of the ore, the viscosity of the slurry and foam, the type of flotation agent and flocculant, the temperature of the slurry, etc. .
What needs to be solved in the design is to calculate the size of the concentrating pool. The geometric parameters are diameter, depth and bottom slope.
1. Diameter calculation The diameter of the concentration tank is the main parameter for selecting the thickener. It is calculated based on the settling area required for the process requirements. which is

Where D is the diameter of the concentration tank, meters;
F——The settlement area required, m 2 . The settlement area can be calculated by processing the production capacity per unit area of ​​the same type of material:

Where Q is the amount of dry ore that is fed into the concentration tank, t/d;
q——Production capacity per unit area, tons/day• m2 . Generally refer to the data of similar production plants. If there is no reference data, it can be selected as shown in the following table.

Concentrated machine unit area production capacity q value

Concentrate name

q (ton / day · m 2 )

Concentrate name

q (ton / day · m 2 )

Mechanical classifier overflow (before flotation)

0.7 to 1.5

Flotation iron concentrate

0.5 to 0.7

Lead oxide and lead concentrates - Copper Concentrate

0.4 to 0.5

Magnetically selected iron concentrate

3.0 to 3.5

Lead sulfide concentrate and lead-copper concentrate

0.6~1.0

Manganese concentrate

0.4 to 0.7

Copper concentrate and copper-bearing pyrite concentrate

0.5 to 0.8

White tungsten ore flotation concentrate and medium mine

0.4 to 0.7

Pyrite concentrate

1.0 to 2.0

Fluorite flotation concentrate

0.8 to 1.0

Molybdenite concentrate

0.4 to 0.6

Barite flotation concentrate

1.0 to 2.0

Zinc concentrate

0.5 to 1.0

Flotation tailings or medium ore

1.0 to 2.0

Antimony concentrate

0.5 to 0.8

 

 

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Note: 1. The data in the table refers to the particle size of 80 ~ 95% - 0.074 mm, the large size of the large value;
2. The concentration of ore discharge is not more than 60-70% for lead, pyrite, copper and zinc sulfide ore concentrates, and other concentrate concentrations are not more than 60%;
3. For fine-grained oxidized ore concentrates with a large amount of mud, the indicators are appropriately reduced.
2. Depth calculation Depth refers to the vertical height of the overflow weir to the top of the bottom of the tank. Its size depends on the concentration required to discharge the product. Generally calculated as follows:

H=HC+HP

Where HC - the vertical height of the pool wall, meters. Generally take

HC = 2.1 ~ 2.6 meters;

Hp - the height of the slope at the bottom of the pool, meters. For the bottom of a single slope:

For double slope bottoms:

Where D is the diameter of the concentration tank, meters;
D 1 ——The diameter of the junction of the two slopes of the concentration pool, meters. Generally take D 1 = (0.3 ~ 0.37) D;
Α——the slope angle of the bottom of the pool, generally 7 to 9 degrees;
1 1 —— the inclination of the outer slope of the bottom of the pool, generally 4 to 5 degrees;
2 2 —— The inclination of the slope at the bottom of the pool is generally 9 to 12 degrees.

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